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Two moles of an equimolar mixture of two alcohols $R_{1} - O H$ and $R_{2} - O H$ are esterified with one mole of acetic acid. If only 80 % of the acid is consumed till equilibrium and the quantities of ester formed under equilibrium are in the mole ratio 3:2. What is the value of equilibrium constant for the esterification of $R_{1} - O H ?$

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answer is 3.67.

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At equilibrium

Ans- 3.67

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