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two moles of an ideal gas $(C_{p, m .} = \frac{5}{2} R)$ heated from 300 K to 600 K at constant pressure.
In this case calculate $Δ S_{gas}$ if process is carried out at constant volume :

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-3 R In 2

5 R In 2

$\frac{3}{2} R$ In 2

3 R In 2

answer is C.

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Detailed Solution

For constant volume,

${ΔS}_{sys} = {nC}_{v}$ in $(\frac{T_{2}}{T_{1}})$

We have given that,

$n = 2 moles$

$\begin{array}{l} T_{2} = 600 K \\ T_{1} = 300 K \end{array}$

$C_{v} = 3 / 2 R$

On putting the values, we get,

${ΔS}_{sys} = 3 R \ln 2$

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