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Q.

two moles of an ideal gas Cp,m.=52R heated from 300 K to 600 K at constant pressure.

In this case   calculate ΔSgas  if process is carried out at constant volume :

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a

-3 R In 2

b

5 R In 2

c

32R  In 2

d

3 R In 2

answer is C.

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Detailed Solution

 For constant volume,

ΔSsys=nCv in  T2T1

We have given that,

n=2 moles 

T2=600KT1=300K

Cv=3/2R

On putting the values, we get,

ΔSsys=3R ln 2


 



 

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