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Two moles of helium gas are taken over the cycle12341 , as shown in the p -T diagram. Assuming the gas to be ideal the work done by the gas in taking it from
1 to 2 is

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400 R

300 R

200 R

500 R

answer is C.

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Detailed Solution

$W_{12} = p (V_{2} - V_{1})$ ( $∴$ constant pressure process)
$= nR (T_{2} - T_{1}) = 2 R (500 - 300) = 400 R$

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