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Two monatomic ideal gases 1 and 2 of molecular masses $m_{1} {and m}_{2}$ respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas 1 to that in gas 2 is given by

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$\sqrt{\frac{m_{1}}{m_{2}}}$

$\sqrt{\frac{m_{2}}{m_{1}}}$

$\frac{m_{1}}{m_{2}}$

$\frac{m_{2}}{m_{1}}$

answer is B.

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Detailed Solution

$V = \sqrt{\frac{γ R T}{M}} \frac{V_{1}}{V_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$

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