Q.

Two natural numbers differ by 3 and their product is 504. The numbers are [[1]] and [[2]].


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answer is 24, 21.

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Detailed Solution

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Two natural numbers differ by 3 and their product is 504. The numbers are 21 and 24.
Given that difference between two natural numbers=3 and product of the natural numbers= 504.
Let’s assume that the two natural numbers are m and m+3.
According to the given condition,
mm+3=504
m2+3m=504
m2+3m-504=0
m2+24m-21m-504=0
mm+24-21m+24=0
(m-21)m+24=0
m-21=0 or m+24=0
 m=21 or m=-24
Therefore, m=21.
And
m+3=21+3 m+3=24
Thus, the two natural numbers are 21 and 24.
 
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