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Two Nicols are oriented with their principal planes making an angle of 60°. The percentage of incident unpolarized light which passes through the system is

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100%

50%

12.5%

37.5%

answer is C.

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Detailed Solution

For 1st Nicol:

$I_{1} = \frac{I_{0}}{2}$

For 2nd Nicol:

$I_{2} = I_{1} \cos^{2} θ = I_{1} \cos^{2} 60 °$

= $= \frac{I_{1}}{4} = \frac{I_{0}}{8} = 12.5 % o f I_{0}$

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