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Two nuclides A and B are isoneutronic. Their mass numbers are 76 and 77, respectively. If the atomic number of A is 32, then the atomic number of B will be

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Detailed Solution

${}_{32}A^{76} {}_{x}A^{77}$

A & B are having same number of neutrons

$∴ (A - Z) if' A' = (A - Z) of B$

$76 - 32 = 77 - x$

$44 = 77 - x \Rightarrow 77 ‐ 44 = 33$

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