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Q.

Two numbers are selected randomly from the $S = {1, 2, 3, 4, 5, 6}$ without replacement. The probability that minimum of the' two numbers is less than 4 is

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a

$\frac{1}{5}$

b

$\frac{1}{15}$

c

$\frac{4}{5}$

d

$\frac{14}{15}$

answer is D.

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Detailed Solution

The favourable cases are 12 :

$\{(1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 3), (2, 4), (2, 5), (2, 6) (3, 4), (3, 5), (3, 6)\}$

The desired probability $= \frac{12}{(6_{C_{2}})} = \frac{12}{15} = \frac{4}{5}$

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