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Q.

Two objects A and B have same shape and area. The Emissivity of A is 0.2 and that of B is 0.8. Each radiates same power. The ratio of their absolute temperatures is

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a

$1 : \sqrt{2}$

b

1:4

c

2:1

d

$\sqrt{2} : 1$

answer is D.

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Detailed Solution

$We know that: E = ε σ {AT}^{4}$

and it is given that both the bodies have same radiating power.
So equating both of them we find that:

$\Rightarrow \frac{T_{1}^{4}}{T_{2}^{4}} = \frac{ε_{2}}{ε_{1}}$

$\Rightarrow \frac{T_{1}}{T_{2}} = \frac{\sqrt{2}}{1}$

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Two objects A and B have same shape and area. The Emissivity of A is 0.2 and that of B is 0.8. Each radiates same power. The ratio of their absolute temperatures is