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Two objects A and B have same shape and area. The emissivity of A is 0.2 and that of B is 0.8. Each radiates same power. The ratio of their absolute temperatures is

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1 : 4

2 : 1

$\sqrt{2}$ : 1

1 : $\sqrt{2}$

answer is D.

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Detailed Solution

E_A = 0.2, E_B = 0.8
$a c c o r d i n g t o s t e p h e n' s l a w P = σ e A T^{4} ∴ e α \frac{1}{T^{4}} : \frac{e_{1}}{e_{2}} = \frac{T_{2}^{4}}{T_{!}^{4}} ∴ T_{A} : T_{b} = \sqrt{2} : 1$

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