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Two objects A and B have same shape and area the emissivity of a is 0.2 and that of B is 0.8 each radiate’s same power the ratio of their absolute temperatures is

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1:4

$\sqrt{2} : 1$

2:1

$1 : \sqrt{2}$

answer is D.

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Detailed Solution

$P o w e r P = A e σ T^{4} T^{4} α \frac{1}{e} \frac{T_{A}}{T_{B}} = {(\frac{e_{B}}{e_{A}})}^{\frac{1}{4}} = {(\frac{0.8}{0.2})}^{\frac{1}{4}} \frac{T_{A}}{T_{B}} \frac{\sqrt{2}}{1}$

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