Two objects of equal masses placed at certain distance from each other attracts each other with a force of F. If one-third mass of one object is transferred to the other object, then the new force will be

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$\frac{2}{9} F$

$\frac{16}{9} F$

$\frac{8}{9} F$

$F$

answer is C.

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Detailed Solution

Let the masses are m and distance between them is $I,$ then $F = \frac{G m^{2}}{I^{2}}$ When 1/3^rd mass is transferred to the other then masses will be $\frac{4 m}{3}$ and $\frac{2 m}{3}$ . So new force will be

$F^{'} = \frac{G \frac{4 m}{3} \times \frac{2 m}{3}}{I^{2}} = \frac{8}{9} \frac{G m^{2}}{I^{2}} = \frac{8}{9} F$

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