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Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is :

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$\frac{20}{3} m$

10 m

5 m

$\frac{10}{3} m$

answer is A.

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Detailed Solution

$x = \frac{2}{3} \times 10 = \frac{20}{3} m$

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