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Two objects of masses $100 g$ and $200 g$ are moving along the same line and direction with a velocity of $2 m / s$ and $1 m / s$ , respectively. They collide and after the collision, the first object moves at a velocity of $1.67 m / s$ . The velocity of the second object is [[1]] $m / s$ .

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Detailed Solution

The velocity of the second object is

1.165 m / s

.
Given,
Mass of one of the objects,

m_{1} = 100 g

In SI unit, mass of the other object,

m_{2} = 0.1 kg

Mass of the other object,

m_{2} = 200 g

In SI unit, mass of the other object,

m_{2} = 0.2 kg

Velocity of

m_{1}

before collision,

v_{1} = 2 m / s

Velocity of

m_{2}

before collision,

v_{2} = 1 m / s

Velocity of

m_{1}

after collision,

v_{3} = 1.67 m / s

By law of conservation of momentum
Total momentum before collision = Total momentum after collision

m_{1} v_{1} + m_{2} v_{2} = m_{1} v_{3} + m_{2} v_{4}

Where velocity of

m_{2}

after collision is

v_{4}

.
On substituting the values, we get

\Rightarrow 0.1 \times 2 + 0.2 \times 1 = 0.1 \times 1.67 + 0.2 \times v_{4}

\Rightarrow 0.4 = 0.167 + 0.2 \times v_{4}

\Rightarrow v_{4} = 1.165 m / s

So after collision, the velocity of the second object is

1.165 m / s .

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Two objects of masses 100 g and 200 g are moving along the same line and direction with a velocity of 2 m/s and 1 m/s, respectively. They collide and after the collision, the first object moves at a velocity of 1.67 m/s. The velocity of the second object is [[1]] m/s.

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Detailed Solution

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Two objects of masses $100 g$ and $200 g$ are moving along the same line and direction with a velocity of $2 m / s$ and $1 m / s$ , respectively. They collide and after the collision, the first object moves at a velocity of $1.67 m / s$ . The velocity of the second object is [[1]] $m / s$ .