Two opposite and equal charges 4 × 10–8 coulomb when placed 2 × 10–2 cm away, from a dipole. If this dipole is placed in an external electric field 4 × 108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180° will be

64 × 10 − 4 Nm and 32 × 10 − 4 J

Two opposite and equal charges 4 × 10–8 coulomb when placed 2 × 10–2 cm away, from a dipole. If this dipole is placed in an external electric field 4 × 108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180° will be

64 × 10 − 4 Nm and 32 × 10 − 4 J

64 × 10 − 4 Nm and 64 × 10 − 4 J

32 × 10 − 4 Nm and 64 × 10 − 4 J

32 × 10 − 4 Nm and 32 × 10 − 4 J

64 × 10 − 4 Nm and 32 × 10 − 4 J

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Two opposite and equal charges 4 × 10^–8 coulomb when placed 2 × 10^–2 cm away, from a dipole. If this dipole is placed in an external electric field 4 × 10⁸ newton/coulomb, the value of maximum torque and the work done in rotating it through 180° will be

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$64 \times 10^{- 4} Nm and 64 \times 10^{- 4} J$

$32 \times 10^{- 4} Nm and 64 \times 10^{- 4} J$

$32 \times 10^{- 4} Nm and 32 \times 10^{- 4} J$

$64 \times 10^{- 4} Nm and 32 \times 10^{- 4} J$

answer is D.

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Detailed Solution

$\begin{matrix} Max . Torque = PE = q \times a \times E \\ = 4 \times 10^{- 8} \times 2 \times 10^{- 4} \times 4 \times 10^{8} \\ = 32 \times 10^{- 4} Nm \\ w = PE (\cos 0^{\circ} - \cos 180^{\circ}) = 2 PE = 64 \times 10^{- 4} J \end{matrix}$

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