Two opposite and equal charges 4×10−8 coulomb when placed 2×10−2 cm away from a dipole. If this dipole is placed in an external electric field 4×108 newton / coulomb the value of maximum torque and the work done in rotating it through 1800 will be

64 × 10 − 4 N m a n d 32 × 10 − 4 J

Two opposite and equal charges 4×10−8 coulomb when placed 2×10−2 cm away from a dipole. If this dipole is placed in an external electric field 4×108 newton / coulomb the value of maximum torque and the work done in rotating it through 1800 will be

64 × 10 − 4 N m a n d 32 × 10 − 4 J

32 × 10 − 4 N m a n d 64 × 10 − 4 J

32 × 10 − 4 N m a n d 32 × 10 − 4 J

64 × 10 − 4 N m a n d 64 × 10 − 4 J

64 × 10 − 4 N m a n d 32 × 10 − 4 J

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Two opposite and equal charges $4 \times 10^{- 8}$ coulomb when placed $2 \times 10^{- 2}$ cm away from a dipole. If this dipole is placed in an external electric field $4 \times 10^{8}$ newton / coulomb the value of maximum torque and the work done in rotating it through $180^{0}$ will be

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$32 \times 10^{- 4} N m a n d 64 \times 10^{- 4} J$

$32 \times 10^{- 4} N m a n d 32 \times 10^{- 4} J$

$64 \times 10^{- 4} N m a n d 64 \times 10^{- 4} J$

$64 \times 10^{- 4} N m a n d 32 \times 10^{- 4} J$

answer is D.

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Detailed Solution

Dipole moment $p = q d = 4 \times 10^{- 8} \times 2 \times 10^{- 4} = 8 \times 10^{- 12} C m$

Maximum torque $= p E \sin θ = p E \sin 90 = 8 \times 10^{- 12} \times 4 \times 10^{8} = 32 \times 10^{- 4} Nm$

Work done in rotating through $180^{0} = p E (\cos θ_{1} - \cos θ_{2}) = = p E (\cos 0 - \cos 180) = 2 p E = 2 \times 32 \times 10^{- 4} = 64 \times 10^{- 4} J$

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