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Q.

Two opposite and equal charges 4×108 coulomb when placed 2×102 cm away, form a dipole. If this dipole is placed in an external electric field 4×108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180° will be 

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a

64×104 Nm  and  64×104 J

b

32×104 Nm  and  32×104 J

c

64×104 Nm  and  32×104 J

d

32×104 Nm  and  64×104 J

answer is D.

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Detailed Solution

Dipole moment p=4×108×2×104=8×1012m

Maximum torque = pE=8×1012×4×108

=32×104Nm

Work done in rotating through 180=2pE

=2×32×104=64×104J

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