Two opposite and equal charges 4×10−8 coulomb when placed 2×10−2 cm away, form a dipole. If this dipole is placed in an external electric field 4×108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180° will be

32 × 10 − 4 Nm and 32 × 10 − 4 J

Two opposite and equal charges 4×10−8 coulomb when placed 2×10−2 cm away, form a dipole. If this dipole is placed in an external electric field 4×108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180° will be

32 × 10 − 4 Nm and 32 × 10 − 4 J

32 × 10 − 4 Nm and 64 × 10 − 4 J

64 × 10 − 4 Nm and 32 × 10 − 4 J

64 × 10 − 4 Nm and 64 × 10 − 4 J

32 × 10 − 4 Nm and 32 × 10 − 4 J

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Two opposite and equal charges $4 \times 10^{- 8} coulomb$ when placed $2 \times 10^{- 2} cm$ away, form a dipole. If this dipole is placed in an external electric field $4 \times 10^{8} newton / coulomb$ , the value of maximum torque and the work done in rotating it through $180 °$ will be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$32 \times 10^{- 4} Nm and 64 \times 10^{- 4} J$

$64 \times 10^{- 4} Nm and 32 \times 10^{- 4} J$

$64 \times 10^{- 4} Nm and 64 \times 10^{- 4} J$

$32 \times 10^{- 4} Nm and 32 \times 10^{- 4} J$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Dipole moment $p = 4 \times 10^{- 8} \times 2 \times 10^{- 4} = 8 \times 10^{- 12} m$

Maximum torque = $pE = 8 \times 10^{- 12} \times 4 \times 10^{8}$

$= 32 \times 10^{- 4} Nm$

Work done in rotating through $180^{\circ} = 2 pE$

$= 2 \times 32 \times 10^{- 4} = 64 \times 10^{- 4} J$

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th