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Q.

Two oxides of a metal contain 50% and 40% metal M respectively. If the formula of the first oxide is MO2, the
formula of the second oxide will be

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a

MO2

b

M2O

c

M2O5

d

MO3

answer is B.

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Detailed Solution

First oxide               Second oxide

M    50%                   M = 40%

O    50%                    Formula = ?

Let the atomic weight of metal = x

 % of M in MO21×x×100x+32=50 (given)

Hence x = 32

 Empirical formula of second oxide:

O=6016=3.75 M=4032=1.25                3.751.25=31.251.25=1

Thus, the formula of second oxide = MO3
 

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