Two oxides of a X contain 50% and 40% of non-metal respectively. If the formula of the first oxide is $X O_{2}$ . Then the formula of second oxide is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$X_{2} O_{5}$

$X O_{3}$

$X_{2} O$

$X_{2} O_{3}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

1st Method:
Given, formula of first oxide is $X O_{2}$ means one mole of
$X = 2$ mole of oxygen in the first oxide.
For second oxide,
40% of $(X),$ we have 60% of oxygen i.e.,
For 40% of $(X),$ . We have $2 \times 60 %$ of oxygen.
$2 \times 60 %$ For 100% of $(X)$ (i.e., one mole) we have, $\frac{2 \times 60}{40} = 3$ moles of oxygen.
$∴$ Formula of second oxide is $= X O_{3}$
2nd Method:
In $X O_{2}, X : O : : 50 : 50$
Mass of oxygen $= 2 \times 16 = 32 g$
Hence, mass of $X = 32 g$
In $X O_{n}, X : O : : 40 : 60$
Mass of $X,$ in this case also remains $= 32 g$
$40 % \equiv 32 g$
$60 % = \frac{32}{40} \times 60 = 48 g$
Mass of oxygen $= 48 g$
$\Rightarrow n = \frac{48}{16} = 3$
Formula of oxide $= X O_{3}$