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Two oxides of Nitrogen, NO and NO₂ react together at 253K and form a compound of Nitrogen, ‘x’. ‘x’ reacts with water to yield another compound of Nitrogen, ‘y’. The shape of the anion of ‘y’ molecule is

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a

Tetrahedral

b

Angular

c

Square planar

d

Pyramidal

answer is B.

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Detailed Solution

$N O + {NO}_{2} \to \underset{X}{N_{2} O_{3}} \overset{H_{2} O}{\to} \underset{Y}{{HNO}_{2}}$

Anion of 'Y' is ${NO}_{2}^{-}$ , which is angular.

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