Two paper screen A and B are separated by a distance of 100 m. A bullet pierces A and B. The hole in B is 10 cm below the hole in A. If the bullet is travelling horizontally at the time of hitting A. Then, the velocity of the bullet at A is

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100 m/s

200 m/s

700 m/s

600 m/s

answer is D.

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Detailed Solution

$h = \frac{1}{2} g t^{2} (i n v e r t i c a l d i r e c t i o n)$

$∴ t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 0.1}{10}} = 0.141 s$

Now, in horizontal direction

$v_{x} = \frac{S_{x}}{t} = \frac{100}{0.141} \approx 700 m / s$

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