Two paper screens A and B are separated by 150 m. A bullet pierces A and B. The hole in B is 15 cm below the hole in A. If the bullet is travelling horizontally at the time of hitting A, then the velocity of the bullet at A is $(s = 10 {ms}^{- 2})$

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$100 \sqrt{3} {ms}^{- 1}$

$200 \sqrt{3} {ms}^{- 1}$

$300 \sqrt{3} {ms}^{- 1}$

$500 \sqrt{3} {ms}^{- 1}$

answer is D.

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Detailed Solution

Range = 150 = ut and $h = \frac{15}{100} = \frac{1}{2} \times {gt}^{2}$

$or t^{2} = \frac{2 \times 15}{100 \times g} = \frac{30}{1000} or t = \frac{\sqrt{3}}{10}$

$u = \frac{150}{t} = \frac{150 \times 10}{\sqrt{3}} = 500 \sqrt{3} {ms}^{- 1}$

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