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Two parallel long straight wires carry currents 10 A and I (>10 A). If the currents in the wires are in the same direction, the magnetic field at a point equidistant between the conductors is 10^-5 T. If the currents in the wires are in the opposite directions, the magnetic field at a point equidistant between the conductors is $3 \times 10^{- 5} T$ . The value of I is

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20 A

12 A

5 A

15 A

answer is A.

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Detailed Solution

$B = \frac{μ_{o}}{2 πr} (i - 10) = 10^{- 5}$

$B^{'} = \frac{μ_{o}}{2 πr} (i + 10) = 3 \times 10^{- 5}$

$\frac{i - 10}{1 + 10} = \frac{1}{3} \Rightarrow i = 20 A$

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