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Q.

Two parallel, long wires are kept 0.20 m apart in vacuum, each carrying current of x A in the same direction. If the force of attraction per meter of each wire is 2×10−6N, then the value of x is approximately :

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a

2.4

b

2

c

1

d

1.4

answer is C.

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Detailed Solution

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Force per unit length =μ0i1i22πd

=μ0⋅x22π×0.2F=2×10−6=4π×10−7×x22π×0.2⇒10−6=10−7x20.2⇒x2=10×0.2=2 ⇒x=2≈1.4A

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