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Two parallel long wires carry currents 18A and 3A. When the currents are in the same direction, the magnetic field at a point midway between the wire is B₁. If the direction of i₂ is reversed, the field becomes B₂. Then the value of B₁/B₂ is

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a

5 : 7

b

7 : 5

c

3 : 5

d

5 : 3

answer is A.

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Detailed Solution

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$B_{1} = \frac{μ_{0} \times 18}{2 π (\frac{d}{2})} - \frac{μ_{0} 3}{\frac{2 πd}{2}}$
Question Image
$= \frac{μ_{0} \times 15}{2 π (\frac{d}{2})}$
$B_{2} = \frac{μ_{0} 18}{2 π (\frac{d}{2})} + \frac{μ_{0} 3}{\frac{2 πd}{2}} = \frac{μ_{0} \times 21}{2 π (\frac{d}{2})}; \frac{B_{1}}{B_{2}} = \frac{5}{7}$

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Two parallel long wires carry currents 18A and 3A. When the currents are in the same direction, the magnetic field at a point midway between the wire is B1. If the direction of i2 is reversed, the field becomes B2. Then the value of B1/B2 is