Two parallel plane sheets 1 and 2 carry uniform charge densities $σ_{1} and σ_{2}$ (see fig.). The electric field in the region I marked is $(σ_{1} > σ_{2})$

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$- \frac{σ_{2}}{2 ε_{0}}$

$\frac{(σ_{1} + σ_{2})}{2 ε_{0}}$

$\frac{(σ_{1} - σ_{2})}{2 ε_{0}}$

$- \frac{σ_{1}}{2 ε_{0}}$

answer is D.

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Detailed Solution

The electric field in the region I is $E = E_{1} + E_{2} = \frac{σ_{1}}{2 ϵ_{0}} + \frac{σ_{2}}{2 ϵ_{0}} \Rightarrow E = \frac{σ_{1} + σ_{2}}{2 ϵ_{0}}$

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