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Q.

Two parallel plates separated by a distance of 5mm are kept at a potential difference of 50V. A particle of mass 10–15 kg and charge 10–11C enters in it with a velocity 107m/s. The acceleration of the particle will be

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a

108 m/s2

b

5 × 105 m/s2

c

2 × 103 m/s2

d

105 m/s2

answer is A.

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Detailed Solution

a=Eqm=Vdqm=505×10310111015=108m/s2

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