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Q.

Two parallel wires carrying currents in the same direction attract each other because of

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a

Potential difference between them

b

Mutual inductance between them

c

Electric forces between them

d

Magnetic forces between them

answer is D.

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Detailed Solution

Two parallel wires carrying currents in the same direction attract each other because of magnetic forces between them
Let wire A and B two parallel wires carrying currents in the same direction attract each other. The wires will attract each other due to magnetic interaction.
The magnitude of the force acting on the current-carrying conductor will be

F = I \times B \times l \dots \dots . (1)

Where,

B = magnitude of magnetic field

I = current flowing in the wire

L = length of the wire

The magnetic field equation is

B = \frac{µ_{0 I}}{2 Πr} \dots \dots (2)

Where,

B = Magnetic field strength

µ_{0} = permeability of vacuum

I = current (flowing in conductor)

r = distance from conductor

By additing value 1 and 2 Let

I_{A}

is the current of wire

A

and

I_{B}

is current of wire

B

F = I_{B} Bl

Where, B= Magnetic field strength

µ_{0}

= permeability of vacuum

I_{B}

= current (flowing in conductor) of wire B
r = distance from conductor

F = I_{B} (\frac{µ_{0 I_{A}}}{2 Πr}) l

Where,

B = Magnetic field strength

µ_{0} = permeability of vacuum

I_{A} = current (flowing in conductor) of wire A

r = distance from conductor

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