Two particles A and B are initially at the origin. They start moving simultaneously along positive x-axis. What is the velocity of B with respect to A?

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3 m/s

$\sqrt{3}$ m/s

$\frac{1}{\sqrt{3}}$ m/s

$\frac{2}{\sqrt{3}}$ m/s

answer is D.

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Detailed Solution

$\begin{array}{rcl} v_{B} & = & S l o p e o f l i n e O B = \tan 60^{0} = \sqrt{3} m / s \\ v_{A} S l o p e o f l i n e O A & = & \tan 30^{0} = \frac{1}{\sqrt{3}} m / s \\ T h e r e f o r e v_{B / A} & = & (\sqrt{3} - \frac{1}{\sqrt{3}}) m / s = \frac{2}{\sqrt{3}} m / s \end{array}$

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