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Q.

Two particles A and B are moving in XY-plane. Their positions vary with time t according to relation
xA (t)=3t, XB (t)=6 YA (t)=t, YB(t)=2+3t2
The distance between two particles at t = 1 is

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a

12

b

3

c

4

d

5

answer is A.

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Detailed Solution

detailed_solution_thumbnail

At t = 1, xA = 3. xB = 6, YA = 1 and yB = 5
So, distance=  xB - xA2 + yB - yA2
= 32 + 42 = 5

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