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Two particles A and B are projected simultaneously in the directions shown in figure with velocities $v_{A} = 25 m / s$ and $v_{B} = 10 \sqrt{3} m / s$ . If they collide in air after 2s, the angle $θ$ is

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$45 °$

$37 °$

$30 °$

$53 °$

answer is D.

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Detailed Solution

For collision,
$v_{A} \sin θ = v_{B} \sin 60 °$
$25 \sin θ = 10 \sqrt{3} \times \frac{\sqrt{3}}{2}$
$\sin θ = \frac{3}{5}$
$o r θ = 37 °$

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