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Q.

Two particles A and B are projected simultaneously in the directions shown in figure with velocities  vA=25 m/s and  vB=103 m/s . If they collide in air after 2s, the angle  θ is
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a

45°

b

37°

c

30°

d

53°

answer is D.

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Detailed Solution

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For collision,
vAsinθ=vBsin60°
25sinθ=103×32
sinθ=35
or θ=37°
 

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