Q.

Two particles A and B are separated by a horizontal distance x. They are projected at the same instant towards each other with speeds u/3 and u at angle of projections 300 and 600 respectively as shown in figure. The time after which the horizontal distance between them becomes zero is: 

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a

2xu

b

4xu

c

x2u

d

xu

answer is A.

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Detailed Solution

Their velocity  of approach is

 v=u/3cos300+ucos600=u 

  t=xv=xu

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