Two particles A and B are separated by a horizontal distance x. They are projected at the same instant towards each other with speeds u3 and u at angle of projections 300 and 600 respectively as shown in the figure. The time after which the horizontal distance between them becomes zero is:

Their velocity of approach isv=u3cos300+ucos600=2u.∴ t=xv=x2u

Two particles A and B are separated by a horizontal distance x. They are projected at the same instant towards each other with speeds u3 and u at angle of projections 300 and 600 respectively as shown in the figure. The time after which the horizontal distance between them becomes zero is:

Their velocity of approach isv=u3cos300+ucos600=2u.∴ t=xv=x2u

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Two particles A and B are separated by a horizontal distance $x .$ They are projected at the same instant towards each other with speeds $u \sqrt{3}$ and $u$ at angle of projections $30^{0}$ and $60^{0}$ respectively as shown in the figure. The time after which the horizontal distance between them becomes zero is:

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$\frac{2 x}{u}$

$\frac{4 x}{u}$

$\frac{x}{2 u}$

$\frac{x}{u}$

answer is B.

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Detailed Solution

Their velocity of approach is

$v = u \sqrt{3} \cos 30^{0} + u \cos 60^{0} = 2 u .$

$∴ t = \frac{x}{v} = \frac{x}{2 u}$

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Two particles A and B are separated by a horizontal distance x. They are projected at the same instant towards each other with speeds u3 and u at angle of projections 300 and 600 respectively as shown in the figure. The time after which the horizontal distance between them becomes zero is:

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