Two particles A and B having charges $20 μ C$ and $- 5 μ C$ respectively are held fixed with a separation of 5cm . At what position a third charged particle should be placed so that it does not experience a net electric force?

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At $5 c m$ from $20 μ C$ on the left side of system

At $5 c m$ from $- 5 μ C$ on the right side

At $1.25 c m$ from $- 5 μ C$ between two charges

At midpoint between two charges

answer is B.

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Detailed Solution

Null point is possible only right side of –5µC.

$E_{N} = + \frac{k (- 5 μC)}{x^{2}} + \frac{k (20 μC)}{(5 + x)^{2}} = 0$

x=5 cm.

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