Q.

Two particles A and B moving in x-y plane are at origin at t = 0 sec. The initial velocity vectors of A and B are uA=8i^  m/s and  uB=8j^  m/s. The acceleration of A and B are constant and are  aA=2i^m/s2   and  aB=2j^m/s2  . Column I gives certain statements regarding particle A and B. Column-II gives corresponding results. Match the statements in column I with corresponding results in Column II.
 

          Column-I

Column-II

A)The time (in seconds) at which velocity  of A relative to B is zerop)162
B)The distance (in metres) between A and B when their relative velocity is zero.q)82
C)The time (in seconds) after t = 0 sec, at which A and B are at same positionr)8
D)The magnitude of relative velocity of A and B  at the instant they are at same position.s)4

      

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a

 A-s; B-p; C-r; D-Q;  

b

A-p; B-p; C-r; D-Q;    

c

A-s; B-q; C-r; D-Q;

d

A-s; B-p; C-p; D-Q;

answer is C.

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Detailed Solution

The initial velocity of A relative to B is    uAB=uAuB=(8i^8j^)m/suAB=82m/s
    acceleration of A relative to B is - 
 aAB=aAaB(2i+2j)m/s2  aAB=22m/s2
since B observes initial velocity and constant acceleration of A in opposite directions, Hence B observes A moving along a straight line. 
From frame of B 
 Hence time when vAB = 0  is t =uABaAB=4 sec. 
The distance between A & B when vAB = 0 is

  S =  u2AB2aAB=m  
The  2uABaAB=8sec
Magnitude of relative velocity when they are at same position in uAB = 82  m/s
 

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