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Q.

Two particles A and B of mass mA and mB respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to the plane. The speeds of the particle A and B are vAand vB respectively, and the trajectories are as shown in the figure. Then
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a

mA<mB  and  νA<vB

b

mAνA<mBvB

c

mAνA>mBvB

d

mA=mB  and  νA=vB

answer is B.

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Detailed Solution

We know that r=mvBq
Here B and q are same; Hence r∝mv
But rA>rB∴mAvA>mBvB

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