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Two particles A and B of masses 1kg and 2kg respectively are kept at very large seperation. They are released from rest and move under their gravitational attraction. If the speed of ‘A’ at certain instance is $4 m s^{- 1}$ speed of ‘B’ at that instance in $m s^{- 1}$ is _____

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answer is 2.

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Detailed Solution

The gravitational attraction force in between the particles acts as internal forces. Since there
is no external force momentum is conserved

From $L.C.M O + O = m_{1} {\vec{V}}_{1} + m_{2} {\vec{V}}_{2}$

$\Rightarrow m_{1} V_{1} = m_{2} V_{2}$

$\Rightarrow 1 \times 4 = 2 \times V_{2} \Rightarrow V_{2} = 2 {ms}^{- 1}$

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