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Q.

Two particles are executing SHM in a straight line with same amplitude A and time period T. At timet=0 , one particle is at displacement x1=+ A  and the other at x2=−A/2 and they are approaching towards each other. After what time they cross each other.

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a

T3

b

T4

c

T6

d

5T6

answer is D.

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Detailed Solution

x1=Acosωt

x2=Asin(ωt−π6)

x1=x2

Acosωt=Asin(ωt−π6)

cosωt=sinωtcos30°−cosωtsin30°

tanωt=3

ωt=π3

2πTt=π3

t=T6

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