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Two particles are projected simultaneously from two points $O$ and $O'$ such that $d$ is the horizontal distance and $h$ is the vertical distance between them. They are projected at the same inclination $α$ to the horizontal with the same velocity $v$ . The time after which their separation becomes minimum is:

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$\frac{d}{v}$

$\frac{d}{2 v \cos α}$

$\frac{2 d}{v \cos α}$

$\frac{d}{v \cos α}$

answer is C.

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Detailed Solution

In any situation (i) or (ii), the distance between two is minimum after crossing the maximum distance by them in horizontal direction with relative velocity in horizontal direction. Thus time after which distance is minimum

$t = \frac{d}{v_{r e l}} = \frac{d}{2 v \cos α}$

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