Two particles are separated at a horizontal distance X as shown in Figure. They are projected at the same line as shown in figure with different initial speeds. The time after which the horizontal distance between them becomes zero :

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$\frac{x}{u}$

$\frac{u}{2 x}$

$\frac{2 x}{x}$

none of these

answer is A.

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Detailed Solution

$Required time = \frac{Relative horizontal distance}{Relative horizontal velocity}$
$= \frac{x}{ucos 60 ° + \frac{u}{\sqrt{3}} \cos 30 °} = \frac{x}{u}$

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