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Two particles are thrown from same point with same velocity with some time interval between them. Horizontal component of projection velocity is u. The Relative angular velocity of the line joining the two particles when they are at same horizontal level is $n \times \frac{g}{u},$ then value of n is

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Detailed Solution

One particle 2/t before max height, other t/2 after max height
Relative velocity perpendicular to line joining them = gt
Relative separation = ut
Relative angular velocity = gt/ut = g/u

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