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Two particles are thrown from the same point in the same vertical plane, as shown in Figure simultaneously. Then the correct statement/s is/are

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Time of flight for B is less than that of A

Projection speed of B is greater than that of A

Horizontal component of velocity for B is greater than that of A

The vertical component of velocities of both A and B are always equal throughout the duration of their times of flight

answer is B, C, D.

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Detailed Solution

maximum heights are same, so $μ_{A} \sin θ_{2} = μ_{B} \sin θ_{1}$ & $\sin θ_{2} > \sin θ_{1}$
$∴ u_{A} < u_{B}, T_{A} = T_{B} R_{A} < R_{B} \Rightarrow u_{A} \cos θ_{2} < u_{B} \cos θ_{1}$

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