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Two particles of equal mass have coordinates (2m, 4m, 6m) and ( 6m, 2m, 8m). Of these one particle has a velocity $v_{1} = (2 \hat{i}) m / s$ and another particle has velocity $v_{2} = (2 \hat{j}) m / s$ at time t = 0. The coordinate of their centre of mass at time t = 1 s will be

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(4 m, 4 m, 7 m)

(5 m, 4 m, 7 m)

(2 m, 4 m, 6 m)

(4 m, 5 m, 4 m)

answer is B.

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Detailed Solution

After 1 s, coordinates of first particle will become (4 m, 4 m, 6 m) and co-ordinates of second particle will become( 6 m, 4 m, 8 m)

$X_{C M} = \frac{4 + 6}{2} = 5 m Y_{C M} = \frac{4 + 4}{2} = 4 m Z_{C M} = \frac{6 + 8}{2} = 7 m$

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