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Q.

Two particles of equal mass ‘m’ are projected from the ground with speed V1 and V2  at angles θ1  and θ2 as shown in fig. Given  θ2>θ1 and V1cosθ1=V2cosθ2 which statements is/are correct?

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a

Particle ‘2’ will be above centre of mass level, when both particles are in air

b

Centre of mass of particles will move along a line inclined at some angle with vertical

c

Centre of mass of particles will move along a vertical line

d

Particle ‘1’ will be above centre of mass level, when both particles are in air

answer is A, D.

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Detailed Solution

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Vcmx=mV1cosθ1+mV2cosθ2m+m=0

So horizontal velocity of CM is zero. Hence CM will move in vertical direction

V2cosθ2=V1cosθ1V2V1=cosθ1cosθ2>1                                                             θ2>θ1  V2>V1V2sinθ2>V1sinθ1

 At any time particle ‘2’ will be at greater height than particle ‘1’.

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