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Q.

Two particles of mass 5kg and 10kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of

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a

80 cm

b

33 cm

c

50 cm

d

67 cm

answer is D.

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Detailed Solution

$d_{1} = \frac{m_{2} d}{m_{1} + m_{2}}$

$\Rightarrow d_{1} = \frac{10 \times 1}{10 + 5} = \frac{2}{3} m = 0.67 m = 67 c m$

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