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Q.

Two particles of mass 'm' each are tied at the ends of a light string of length '2a'. The whole system is kept on frictionless horizontal surface with the string held tight so
that each mass is at a distance 'a' from the center P (as shown in figure). Now, the midpoint of the string is pulled vertically upwards with a small but constant force F. As a
result, the particles move towards each other on the surface. The magnitude of acceleration, when the separation between them becomes 2x is:

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a

F2ma2x2x

b

F2maa2x2

c

F2mxa2x2

d

F2mxa

answer is B.

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Detailed Solution

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2Txcosθ=FTx=Fa2a2x2
Acceleration  of  particle =Txsinθm=F2mxa2x2

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