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Two particles of masses 5 g and 3 g are separated by a distance of 40 cm. The centre of mass of the system of these two particles

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lies at a distance of 15 cm from 5 g particle

lies at a distance of 25 cm from 5 g particle

lies at a distance of 10 cm from 3 g particle

lies at the mid point of the line joining the two particles

answer is A.

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Detailed Solution

$X_{c o m} = (\frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}})$

from the 5g particle

$X_{c o m} = \frac{5 (0) + 3 (40)}{8} = 15 c m$

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