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Two particles of masses ‘m’ and ‘2m’ are at a distance ‘3r’ apart at the ends of a straight line AB. C is the centre of mass of the system. The magnitude of the gravitational force on a unit mass placed at C due to the masses is

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$\frac{3 G m}{2 r^{2}}$

Zero

$\frac{7 Gm}{4 r^{2}}$

$\frac{9 G m}{4 r^{2}}$

answer is B.

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Detailed Solution

$F = \frac{{Gm}_{1} m_{2}}{R^{2}}, F_{net} = F_{2} - F_{1}$

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