Q.

Two particles of masses m1 and m2 in projectile motion have velocities  v1  and v2  respectively at time t = 0. They collide at time to. Their velocities become v21  and  v11  at time 2to while still moving in air. The value of |(m1v11+m2v21)(m1v1+m2v2)|   is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

zero

b

(m1+m2)gto

c

2(m1+m2)gto

d

12  (m1+m2)gto

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

A/c  L.C.L.M
mv1=mvmv1=m(u+at)m1v12+m2v22=mv1+2gt0+mv2+2gto
 

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon