Two particles of masses m1 and m2, m1 > m2 move in circular paths under the action of their gravitational attraction, then:

radius of circular path of m 1 is less than that of m 2

radius of circular path of m 1 is less than that of m 2

radius of circular path of m 1 is more than that of m 2

radius of circular path of m 1 is less than that of m 2

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Two particles of masses m₁ and m₂, m₁ > m₂ move in circular paths under the action of their gravitational attraction, then:

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they move in the same circle

radius of circular path of m₁ is more than that of m₂

radius of circular path of m₁ is less than that of m₂

each moves along circular path of variable radius

answer is C.

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As both particles revolve around their common center of mass. Since $m_{1}$ is heavy hence COM will be more closer to $m_{1}$ . Hence $r_{1} < r_{2}$

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